$\sin{(90^\circ-\theta)}$ $\,=\,$ $\cos{\theta}$
Let’s assume that a Greek alphabet Theta is considered to denote an angle in first quadrant of the coordinate system. The right angle is written as ninety degrees as per the sexagesimal system in mathematics. Now, subtract the angle theta from the right angle and it is written as $90^\circ-\theta$ mathematically. The difference of them obviously represents an angle in the first quadrant of the coordinate system.
The sine of that angle is written as $\sin{(90^\circ-\theta)}$ and its value is mathematically equal to cosine of angle theta.
$\sin{(90^\circ-\theta)}$ $\,=\,$ $\cos{\theta}$
It is called the cofunction identity of sine in trigonometry.
The sine of ninety degrees minus theta trigonometric identity is also alternatively written as follows.
$\sin{\Big(\dfrac{\pi}{2}-x\Big)}$ $\,=\,$ $\cos{x}$
The sine of ninety degrees minus theta identity is mainly used in two cases in trigonometry.
The sine of angle ninety degrees minus theta identity can be derived in two distinct methods in mathematics.
Learn how to derive the sine ninety minus theta formula in trigonometry by a trigonometric identity.
Learn how to prove the sine ninety minus theta identity geometrically by constructing a right triangle in first quadrant of coordinate system.
Assume that $\theta \,=\, 30^\circ$.
Now, let’s evaluate both sine of ninety degrees minus theta and cosine of angle theta by replacing the theta with thirty degrees.
$(1).\,\,\,$ $\sin{(90^\circ-30^\circ)}$ $\,=\,$ $\sin{(60^\circ)}$ $\,=\,$ $\dfrac{\sqrt{3}}{2}$
$(2).\,\,\,$ $\cos{(30^\circ)}$ $\,=\,$ $\dfrac{\sqrt{3}}{2}$
$\,\,\,\therefore\,\,\,\,\,\,$ $\sin{(90^\circ-30^\circ)}$ $\,=\,$ $\cos{(30^\circ)}$ $\,=\,$ $\dfrac{\sqrt{3}}{2}$
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