$\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{x^{\displaystyle n}-a^{\displaystyle n}}{x-a} \,=\, n.a^{\displaystyle n-1}}$
Let $x$ be a variable, and $a$ and $n$ be two constants. Let’s assume that two quantities are expressed in exponential form as $x^{\displaystyle n}$ and $a^{\displaystyle n}$.
The ratio of the above two indeterminate quantities is written as follows in mathematics.
$\dfrac{x^{\displaystyle n}-a^{\displaystyle n}}{x-a}$
The limit of this rational expression as the value of $x$ approaches to $a$ is written in the following mathematical form.
$\implies$ $\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{x^{\displaystyle n}-a^{\displaystyle n}}{x-a}}$
The limit of the $x$ raised to the power $n$ minus $a$ raised to the power $n$ by $x$ minus $a$ as the value of $x$ is closer to $a$, is equal to the $n$ times $a$ raised to the power $n$ minus $1$.
$\implies$ $\displaystyle \large \lim_{x \,\to\, a}{\normalsize \dfrac{x^{\displaystyle n}-a^{\displaystyle n}}{x-a}}$ $\,=\,$ $n \times a^{\displaystyle n-1}$
It can be called the power-difference limit rule in ratio form.
Learn how to derive the power-difference law of limits in ratio form in calculus mathematically.
List of the questions on power-difference property of limits in ratio form with solutions.
A free math education service for students to learn every math concept easily, for teachers to teach mathematics understandably and for mathematicians to share their maths researching projects.
Copyright © 2012 - 2023 Math Doubts, All Rights Reserved