Proof of Equation of a circle centered at the origin
The circle centered at the origin of the two dimensional space is written in following mathematical form.
$x^2+y^2$ $\,=\,$ $r^2$
Let us learn how to derive the equation of a circle in standard mathematical form when the center (or centre) of a circle is exactly located at the origin of the bi-dimensional space.
Construction of a Triangle inside a Circle
A right triangle (or right angled triangle) should be constructed for deriving a standard equation of a circle when the circle is centered at the origin of the two dimensional cartesian coordinate system.

A right angled triangle inside a circle whose center (or centre) is exactly located at origin in the two dimensional cartesian coordinate system can be constructed as per the following steps.
- Let’s denote the origin of the two-dimensional cartesian coordinate system by $O$ and draw a circle, which is centered at the origin. It means, the center (or centre) of circle $C$ is exactly located at the origin of the two dimensional space.
- Consider a point on the circumference of circle and it is denoted by $P$. Let us assume that the point $P$ is $x$ and $y$ units away from the origin in both horizontal and vertical directions. Therefore, the point $P$ in coordinate form is written as $P(x, y)$.
- Connect the point $P$ and the centre (or center) or origin by a straight line and it represents the radius of the circle geometrically. Let’s assume that the radius of the circle is $r$ units.
- Draw a perpendicular line to $x$-axis from point $P$ and it intersects the horizontal axis at point $Q$. Thus, it forms a right angled triangle, which is written as $\Delta QOP$ or $\Delta QCP$.
Calculate the lengths of sides of Triangle
In $\Delta QCP$ or $\Delta QOP$, the opposite side is $\overline{PQ}$, the adjacent side is $\overline{OQ}$ or $\overline{CQ}$ and the hypotenuse is $\overline{OP}$ or $\overline{CP}$. Their lengths are written in mathematical form as $PQ, OQ$ or $CQ$ and $OP$ or $CP$ respectively.

It is time to calculate the length of each side of the right angled triangle.
- $OQ$ $\,=\,$ $CQ$ $\,=\,$ $x$
- $PQ$ $\,=\,$ $y$
- $OP$ $\,=\,$ $CP$ $\,=\,$ $r$
Write the relation between the sides
According to the Pythagorean Theorem, the lengths of all three sides of right angled triangle $POQ$ or $PCQ$ can be written as a mathematical relation.

${CP}^2$ $\,=\,$ ${CQ}^2+{PQ}^2$
$\implies$ ${OP}^2$ $\,=\,$ ${OQ}^2+{PQ}^2$
We know that the $CQ$ or $OQ$ is length of opposite side, $PQ$ is length of adjacent side and $OP$ or $CP$ is length of hypotenuse. Now, substitute the lengths of them in the above mathematical equation.
$\implies$ $r^2$ $\,=\,$ $x^2+y^2$
$\,\,\,\therefore\,\,\,\,\,\,$ $x^2+y^2$ $\,=\,$ $r^2$
It is a standard mathematical equation of a circle when the circle is centered at the origin of two dimensional cartesian coordinate system.
