$(a+b)^2 = a^2+2ab+b^2$
Let’s denote two quantities by two literals $a$ and $b$ in mathematics.
$(a+b)^2$
The square of sum of two terms is equal to the $a$ squared plus $b$ squared plus $2$ times product of $a$ and $b$.
$(a+b)^2$ $\,=\,$ $a^2+b^2+2ab$
In mathematics, the $a$ plus $b$ whole squared algebraic identity is called in three ways.
In mathematics, the square of the sum of two terms is used as a formula in two cases.
The square of the sum of two terms is expanded as the sum of squares of both terms and two times the product of them.
$\implies$ $(a+b)^2 \,=\, a^2+b^2+2ab$
The sum of squares of the two terms and two times the product of them is simplified as the square of the sum of two terms.
$\implies$ $a^2+b^2+2ab \,=\, (a+b)^2$
$(1) \,\,\,$ Find $(3x+4y)^2$
Now, take $a = 3x$ and $b = 4y$ and substitute them in the expansion of the formula for evaluating its value.
$\implies$ $(3x+4y)^2$ $\,=\,$ $(3x)^2+(4y)^2+2(3x)(4y)$
$\implies$ $(3x+4y)^2$ $\,=\,$ $9x^2+16y^2+2 \times 3x \times 4y$
$\implies$ $(3x+4y)^2$ $\,=\,$ $9x^2+16y^2+24xy$
$(2) \,\,\,$ Simplify $p^2+25q^2+10pq$
$\implies$ $p^2+25q^2+10pq$ $\,=\,$ $p^2+(5q)^2+10pq$
$\implies$ $p^2+25q^2+10pq$ $\,=\,$ $p^2+(5q)^2+2 \times 5 \times p \times q$
$\implies$ $p^2+25q^2+10pq$ $\,=\,$ $p^2+(5q)^2+2 \times p \times 5 \times q$
$\implies$ $p^2+25q^2+10pq$ $\,=\,$ $p^2+(5q)^2+2 \times p \times 5q$
$\implies$ $p^2+25q^2+10pq$ $\,=\,$ $p^2+(5q)^2+2(p)(5q)$
Now, take $a = p$ and $b = 5q$, and simplify the algebraic expression by the $(a+b)^2$ identity
$\implies$ $p^2+25q^2+10pq$ $\,=\,$ $(p+5q)^2$
The $a$ plus $b$ whole square identity can be derived in mathematics in two different methods.
Learn the algebraic approach to derive the expansion of the $a+b$ whole square formula by the multiplication.
Learn the geometric method to derive the expansion of the $a+b$ whole squared identity by the areas of geometric shapes.
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